elationship between voltage, current, and resistance in electrical circuits. Conducting investigations into these concepts allows students and enthusiasts to develop a practical understanding of how electrical components behave and ho
tage and current simultaneously: Measure Voltage: Use a multimeter across the load. Measure Current: Connect the multimeter in series with the load. Calculate Power: Multiply the measured voltage and current (P = V Ć I). Alternatively, if resistance is known: Use P = VĀ² / R to calculate power.
ing applications, ensuring safety, efficiency, and innovation in circuit design. In essence, this experiment not only confirms a foundational law of electricity but also equips students and practitioners with the skills necessary to analyze and interpret electrical phenomena, fostering a
current? Solution: \[ I = \frac{P}{V} = \frac{60}{60} = 1\,A \] Answer: 1 ampere 5. Resistance Calculation from Power and Current Question: A resistor carries 3 A current and dissipates 36 W. What is its resistance? Solution: Using \( P = I^2 \times R \): \[ R = \frac{P}{I^2} = \fra
